[Advanced-java] OOP's Question

[Brian Mulanda]

Jayprakash,

I understand why you question this behavior; it's not entirely obvious
which methodA() would be invoked. At first I thought it would be C's 
methodA(). However, tests prove that it is A's methodA() that get's 
invoked. 

Now the question is why. Intuition suggests, it's because the chain of 
method calls leading to the invocation of methodA() originated from A. 
So the JVM looks for methodA() "bottom-up" with A at the bottom and C 
at the top. This may not be the correct explanation.

So, it's worth investigating how method invocation works in such a case. 
When you find out, please share with us your findings.

_____
Brian

--- "G.N.V. Jayprakash" <gnvjp at hotmail.com> wrote:

> 
> Hi,
>      I have a question in Object Oriented Programming:
>  
> A extends B. B extends C. There is a public method methodA() implemented in C. methodA() is also
> overridden in A.
>  
> There is a flow starting from A from preProcessRequest()  implemented in A. preProcessRequest()
> is also implemented in B. 
>  
> Now preProcessRequest() in A invokes super.preProcessRequest(). The control goes to the
> preProcessRequest() in B.
> preProcessRequest() method implementation in B invokes methodA().
>  
> Now the question is: Will the methodA() implemented in C will be invoked or the methodA()
> implemented in A will be invoked? Why?.
>  
> Thanks & Regards,Jayprakash
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